tan8+2(2tan 8+1) =5tan+sin2
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Answer:
Weknowthat,tanA=cotA−2cot2A
LHS=tan 16
π +2tan 8π +4=cot
16π −2cot 8 +2(cot 8π −2cot 4π )+4=
cot16π+4−4=cot 16π
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