Question

Tan9°+Tan81°-Tan27°-Tan63°​

Answer 1

tan 81 -tan63 +tan 9 - tan 27=

tan(90-9)-tan(90-27)+tan9-tan27

=cot9-cot27+tan9-tan27

=(sec^2(9)/tan(9))-(sec^2(27)/tan(27))

=(1/(sin(9)cos(9))-((1/(sin(27)cos(27))

=(2/sin(18))-(2/(sin(54))

=4

Answer 2

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Explanation: is given in the above attachment

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