Question

tanA. √(1 − ²A) is equal to​

Answer 1

Answer:

3

Step-by-step explanation:

Given that, tanA=12andtanB=13

Now,  tan(2A+B)=tan2A+tanB1−tan2A⋅tanB ...(i)

Also, tan2A=2tanA1−tan2A=2⋅121−14=43

From Eq. (i), tan(2A+B)=43+131−43⋅13=43+139−49=5359=3