TanA=-1/2and tanB=-1/3 ten A+B=?
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Given that Tan (A+B) tan(A + B)
= tan A + tan B / 1 - tan A * tan B
= (1 / 2 + 1 / 3) / 1 - ( 1 / 2 * 1 / 3)
= (3 + 2 / 6) / (1 - 1 / 6)
= (5 / 6 ) / (5 / 6)
= 1
therefore tan (a+b)=tan 45
tan 45=1 so (a+b)=45
= tan A + tan B / 1 - tan A * tan B
= (1 / 2 + 1 / 3) / 1 - ( 1 / 2 * 1 / 3)
= (3 + 2 / 6) / (1 - 1 / 6)
= (5 / 6 ) / (5 / 6)
= 1
therefore tan (a+b)=tan 45
tan 45=1 so (a+b)=45
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