Question

TanA=1/3, find the other trigonometrical ratios
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Answer 1

Step-by-step explanation:

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Q:-TanA=1/3, find the other trigonometrical ratios

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Given :-

$⟹TanA= \frac{1}{3}$

∴ $⟹CotA = \frac{3}{1} = 3$

$⟹Tan A= \frac{1}{3}$

${Tan}^{2} A = \frac{1}{9}$

$⟹1 + {Tan}^{2} A = 1 + \frac{1}{9} = \frac{9 + 1}{9} = \frac{10}{9}$

∴ $⟹SecA = \sqrt{ \frac{10}{9} }$

$⟹CosA = \frac{3}{ \sqrt{10} }$

$⟹ {Cos}^{2} A= \frac{9}{10}$

$⟹1 - {Cos}^{2} A = 1 - \frac{9}{10}$

$⟹ {Sin}^{2} A = \frac{10 - 9}{10} = \frac{1}{10}$

$⟹SinA = \sqrt{ \frac{1}{10} } = \frac{1}{ \sqrt{10} }$

∴$⟹CosecA = \sqrt{10}$

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HOPE IT HELPS YOU..

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Thankyou:)

Answer 2

Step-by-step explanation:

sin A=1/√10

cos A =3/√10

cosec A=√10

sec A=√10/3

cot A=3