tanA=1/3, tanB=1/4
Where 0πsin(A+B)
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As you can see, after the first assignment of variables (a = b), two steps were done at once. ..... is very simple, yet it requires some mathematical knowledge, like what is log1/4 4. ...... -1/3. Again, we get -1/3 as an answer. Math can be very easy if you think ..... cotAcotB - (tanA + tanB)/(1 - tanAtanB) * (tanA + tanB)/( tanAtanB)
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