tanA =1/√7 and A is acute angle then cosec^A-sec^A/cosec^A+sec^A
Answers
Answered by
0
Answer:
Step-by-step explanation:
Tan = 1÷ /7 = p/b
P = K, b = /7k ( K is constant)
H² = b²+p²
= (/7)²+(1)²
H² = 7+1
H = /8 = 2/2
Cosec = h÷p = 2/2÷1
Sec = h÷b = 2/2÷/7
Cosec-sec/cosec+sec
2/2-2/2÷7 ÷ 2/2+2/2÷7
2/2(1-1÷/7) ÷ 2/2(1+1÷/7)
2/2 cancels
/7-1 ÷ /7 ÷ /7+1 ÷ 7
/7-1 ÷ 7 × 7 ÷ /7+1
= /7-1 ÷ /7+1
dishabucha:
Plz mark as brainliest
ans is 3/4 but u didn't get that ans I know ans but I don't know how to solve that question
Similar questions