Question

tanA =1/√7 and A is acute angle then cosec^A-sec^A/cosec^A+sec^A​

Answer 1

Answer:

Step-by-step explanation:

Tan = 1÷ /7 = p/b

P = K, b = /7k ( K is constant)

H² = b²+p²

= (/7)²+(1)²

H² = 7+1

H = /8 = 2/2

Cosec = h÷p = 2/2÷1

Sec = h÷b = 2/2÷/7

Cosec-sec/cosec+sec

2/2-2/2÷7 ÷ 2/2+2/2÷7

2/2(1-1÷/7) ÷ 2/2(1+1÷/7)

2/2 cancels

/7-1 ÷ /7 ÷ /7+1 ÷ 7

/7-1 ÷ 7 × 7 ÷ /7+1

= /7-1 ÷ /7+1