tanA=1 and tanB=√3,then cosA.cosB-sinA.sinB is equal to?
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Answered by
46
If tanA = 1; tanB
= √3 therefore,
A is equal to 45 degree and B is equal to 60 degree hence,
tan 45 degree is equal to 1 and tan 60 degree is equal to √3 Solution 1 – cos A.cos B – sin A.sinB
which is equal to, (cos 45 degree) (cos 60 degree) - (sin 45 degree) (sin 60 degree)
which is, 1/2 x 1/√2 - 1/√2 x √3/2 = 1-√3/2√2
= √3 therefore,
A is equal to 45 degree and B is equal to 60 degree hence,
tan 45 degree is equal to 1 and tan 60 degree is equal to √3 Solution 1 – cos A.cos B – sin A.sinB
which is equal to, (cos 45 degree) (cos 60 degree) - (sin 45 degree) (sin 60 degree)
which is, 1/2 x 1/√2 - 1/√2 x √3/2 = 1-√3/2√2
Answered by
12
Answer:
Step-by-step explanation:
If tanA = 1; tanB
= √3 therefore,
A is equal to 45 degree and B is equal to 60 degree hence,
tan 45 degree is equal to 1 and tan 60 degree is equal to √3 Solution 1 – cos A.cos B – sin A.sinB
which is equal to, (cos 45 degree) (cos 60 degree) - (sin 45 degree) (sin 60 degree)
which is, 1/2 x 1/√2 - 1/√2 x √3/2 = 1-√3/2√2
Read more on Brainly.in - https://brainly.in/question/738718#readmore
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