Math, asked by oraonpawan875, 5 months ago

tanA/1-cot A+cotA/1-tanA=1+tanA+cotA​

Answers

Answered by afrithafathima27
0

Step-by-step explanation:

Proof:

L.H.S = tanA/1-cotA + cotA/1-tanA

= tanA/1-1/tanA + 1/tanA/ I-tanA

= tanA/tanA-1/tanA + 1/ tanA(1-tanA)

= tan A2A/tanA-1 - 1/ tanA(tanA-1)

= tan A3A-1/tanA(tanA-1)

= (tanA-1)(tan A2A+1+tanA)/ tanA(tanA-1)

= tan A2A/tanA + 1/tanA + tanA/tanA

= tanA + cotA + 1

= 1+ tanA + cotA = R H S

Hope it help you.

Pls mark me as brainliest

Answered by sandy1816
0

Answer:

your answer attached in the photo

Attachments:
Similar questions