Math, asked by ysdavn7, 9 months ago

tanA/1-cotA. + cotA/1- tanA​

Answers

Answered by prachi2275
0

Answer:

below

Step-by-step explanation:

tanA/(1–1/tanA) +cotA/(1-tanA)

tan^2A/(tanA-1) +cotA/(1-tanA)

-tan^2A/(1-tanA) +cotA/(1-tanA)

(-tan^2A+cotA)/(1-tanA)

(-tan^2A+1/tanA)/(1-tanA)

(-tan^3A+1)/tanA(1-tanA)

(1-tan^3A)/tanA(1-tanA)

(1-tanA)(1+tanA+tan^2A)/tanA(1-tanA)

(1+tanA+tan^2A)/tanA

(1+tan^2A+tanA)/tanA

(sec^2A+tanA)/tanA

sec^2A/tanA +tanA/tanA

1/cos^2AtanA+1

cosA/cos^2AsinA+1

1/cosAsinA+1

secAcosecA+1

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