Math, asked by Soomaiqa7395, 11 months ago

TanA/1-cotA+cotA/1-tanA=secA.cosecA+1

Answers

Answered by sandy1816
0

Step-by-step explanation:

LHS

=sinA/cosA÷1-cosA/sinA+cosA/sinA÷1- sinA/cosA

=sinA/cosA×sinA/sinA-cosA+cosA/sinA×cosA/cosA-sinA

=sin²A/cosA(sinA-cosA)+cos²A/sinA(cosA-sinA)

=sin²A/cosA(sinA-cosA)-cos²A/sinA(sinA-cosA)

=sin³A-cos³A/sinAcosA(sinA-cosA)

=(sinA-cosA)(sin²A+sinAcosA+cos²A)/ sinAcosA(sinA-cosA)

=1+sinAcosA/sinAcosA

=1/sinAcosA+sinAcosA/sinAcosA

=cosecAsecA+1

=RHS

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