Question

tana (1 + sec 2a) = tan 2a​

Answer 1

$\huge\underline\mathrm\red{Answer}$

$l \: h \: s \: = tan \: a(1 + sec 2a) \\ \\ = tan \: a(1 + \frac{1}{cos \: 2a} ) \\ \\ = ( \frac{1 + cos2a}{cos2a} ) \\ \\ = \frac{1}{cos2a} \: \\ \\ (tan \: a \times 2 {cos}^{2} a) \\ \\ ( \frac{ \sin(a) }{cos \: a} \times 2 {cos}^{2} a) \\ \\ = \frac{sin2a}{cos2a} \\ \\ = tan2 \: a \\ \\ lhs \: = \: rhs$

Answer 2

Step-by-step explanation:

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