Question

tanA(1 + sec 2A)
tan 2A
sin a + cosa
tan 2a + sec 2a
Cosa - sina​

Answer 1

LHS = tan A ( 1 + sec 2A )

.......= tan A ( 1 + 1/ cos 2A )

.......= tan A ( cos 2A + 1 ) / ( cos 2A )

.......= tan A ( 2 cos^2 A ) / ( cos 2A )

......= ( sin A / cos A ) ( 2 cos^2 A ) / ( cos 2A )

.......= ( 2 sin A cos A ) / cos 2A

.......= sin 2A / cos 2A

.......= tan 2A

........=RHS

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