Math, asked by leena1903, 9 months ago

tanA/1+secA +1+secA/tanA =?

Answers

Answered by Anonymous

9

Answer:

plz ..

see the attachment

q

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Answered by mahewish59

0

Answer:

TanA/1+secA+1+secA/tanA

tan2A+(1+sec)2/(1+secA)tanA

=tan2A+1+sec2A+2secA/tanA (1+secA)

=sec2A+sec2A+2secA/tanA (1+secA)

=2sec2A+2secA/tanA (1+secA)

=2secA (secA+1)/tanA (1+secA)

=2secA/tanA=2×1/cosA/sinA/cosA

=2/sinA=2cosecA

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