Math, asked by shubh222250, 5 months ago

{tanA/(1+secA)}-{tanA/(1-secA)}

Answers

Answered by krishnasinghkm

4

Answer:

tanA+tanA×secA-tanA-tanA×secA

tanA×secA-tanA×secA

secA(tanA-tanA)

secA×0

0

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