Question

tanA+√1-sinA/1+sinA=secA
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Answer 1

Answer:

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Answer 2

Answer:

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$tan \: A \: + \sqrt{ \frac{1 - sin \: A}{1 + sinA} }$

$tan \: A + \sqrt{ \frac{(1 - sin \: A) {}^{2} }{1 - sin {}^{2} \: A } }$

$tan \: A + \sqrt{ \frac{(1 - sin \: A) {}^{2} }{cos {}^{2} \: A} }$

$tan \: A + \frac{1 - sin \: A}{cos \: A}$

$tan \: A \: + sec \: A - tan \: A$

$= sec \: A$