Math, asked by crazy3717, 3 months ago

tanA/(1+tan²A)+cotA/(1+cot²A)=sinAcosA

Answers

Answered by biligiri

0

Step-by-step explanation:

=> tan A/sec²A + cot A/cosec² A [ 1 + tan²A = sec²A and 1 + cot²A = cosec² A ]

=> (sin A cos²A)/cos A + (cos A sin²A)/sin A

=> 2 cos A sin A

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