Math, asked by yadramgola51gmailcom, 4 months ago

tanA + 1/tanA = secA.cosecA

Answers

Answered by Anonymous

0

Step-by-step explanation:

tanA + 1/tanA

tan²A+1/tanA

Sec²A/tanA

(1/cos²A)/(sinA/CosA)

1/sinA.cosA

secA.cosecA

Answered by kookliet

7

Hope this helps you...

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