tana=16/63 then find cos2a
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Answered by
0
TanA = 16/63 = p/b
p= 16, b = 63 , h= ?
we know that,
(h)²= (p)²+(b)²
= (16)²+(63)²
= 256+3969= 4225
h = ✓4225 = 65.
Therefore,
Cos A = b/h = 63/65
p= 16, b = 63 , h= ?
we know that,
(h)²= (p)²+(b)²
= (16)²+(63)²
= 256+3969= 4225
h = ✓4225 = 65.
Therefore,
Cos A = b/h = 63/65
Answered by
1
use pythagoras theorem to find the third side...
u will get 65
then use cos theta =adj/hyp.
therefore....
cos 2a
::2(63/65)
::126/65
thanks........!!!!!
u will get 65
then use cos theta =adj/hyp.
therefore....
cos 2a
::2(63/65)
::126/65
thanks........!!!!!
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