Question

tanA=2/3 and tanB=3/7 so( A+B)=?​

Answer 1

$\huge\mathfrak\red{Solution}$

TanB=1/2

Tan(A+B)=2

(TanA+ TanB)/(1-tanAtanB)=2

(TanA+1/2)=2(1-tanAtanB)

TanA+1/2=2-2*tanA*1/2

TanA+1/2=2-tanA

TanA+TanA=2-1/2

2tanA=3/2

TanA= 3/4

Checking answer::> we have, tanA= 1/2

and, we got, tanB=3/4

So, tan(a+b)= (tanA+tanb)/(1-tanatanb)

=(1/2+3/4)/(1-1/2*3/4)

=(10/8)/(5/8)

=10*8/8*5

=80/40

=2

Answer 2

Answer:

Step-by-step explanation:

Answer is 192 cone.

Step by step :-