Question

tanA^2-cotA^2/sinA^2-cosA^2=secA^2+cosecA^2

Answer 1

Step-by-step explanation:

<br> cotA/2-tanA/2=(cosA/2)/(sinA/2)-(sinA/2)/(cosA/2) <br> =(cos^(2)A/2-sin^(2)A/2)/(sinA/2cosA/2) <br> =cosA/(1/2.(2sinA/2cosA/2)) <br> =(2cosA)/(sinA)=2cotA = RHS. Hence Proved.