tanA=3/4 and tanB=4/3 then (A+B)=?
Answers
Answered by
17
Heya
_______________________________
Tan ( A + B ) =
{Tan A + Tan B }/ ( 1 - Tan A × Tan B )
Formula
=>
Tan A + Tan B =
Tan ( A + B ) × { 1 - Tan A × Tan B }
Here Tan A = 3/4 And Tan B = 4/3
=>
(3/4) + (4/3) = Tan ( A + B ) { 1 - 1 }
=>
Tan ( A + B ) = 25/12×0
=>
Tan ( A + B ) = infinity.
=>
Tan ( A + B ) = Tan ( 90° )
becoz Tan ( 90 ) is infinity.
=>
A + B = 90°
_______________________________
Tan ( A + B ) =
{Tan A + Tan B }/ ( 1 - Tan A × Tan B )
Formula
=>
Tan A + Tan B =
Tan ( A + B ) × { 1 - Tan A × Tan B }
Here Tan A = 3/4 And Tan B = 4/3
=>
(3/4) + (4/3) = Tan ( A + B ) { 1 - 1 }
=>
Tan ( A + B ) = 25/12×0
=>
Tan ( A + B ) = infinity.
=>
Tan ( A + B ) = Tan ( 90° )
becoz Tan ( 90 ) is infinity.
=>
A + B = 90°
Answered by
0
Answer:
90°
Step-by-step explanation:
solve by using following formula
Tan(A+B)×{1-tanA×tanB}
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