Question

TanA=3/4 then find the value of 1-cosA/1+cosA

Answer 1

Answer:

-3/5

Step-by-step explanation:

$\tan \alpha = \frac{3}{4} \\ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \frac{3}{4} \\ \cos( \alpha ) = 4 \\ \sin( \alpha ) = 3 \\ \frac{1 - \cos( \alpha ) }{1 + \cos( \alpha ) } = \frac{1 - 4}{1 + 4} = \frac{ - 3}{5}$

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Answer 2

Answer:

Let ABC be a right triangle right angled at B.

tanA = 3/4

✔ BC/AB = 3/4

THEREFORE, BC = 3 AND AB = 4

NOW,

From the figure, AC = 5

cosA = AB/AC

= 4/5

Now,

✔ 1-cosA/1+cosA

$\frac{1 - \frac{4}{5} }{1 + \frac{4}{5} } \\ \frac{ \frac{5 - 4}{5} }{ \frac{5 + 4}{5} } \\ \frac{ \frac{1}{5} }{ \frac{9}{5} } \\ \frac{1}{9}$

Therefore, the answer is 1/9.

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