tana=3/5 tanb=5/12 find tan a-b a&b are acute angles
Answers
Answer:
sin A = 3/5, so cos A = 4/5 and tan A = 3/4
cos B = 12/13, so sin B = 7/13 and tan B = 7/12
A. As given in the question
tan A - tan B/1 + tan A tan B
= (3/4) - (7/12)/1 + (3/4)(7/12)
= (3/4) - (7/12) + (3*12/4*7)
= (3/4) =(7/12) +(9/7)
= 1.452380952 (WRONG)
B. As what should have been in the question, with brackets,
(tan A - tan B)/(1 + tan A tan B)
= [(3/4)-(7/12)]/[1 +(3/4)(7/12)
= 0.166666666/1.4375
= 0.115942029 (RIGHT)
Check: A = arc tan 0.75 = 36.86989765 deg, B = arc tan (7/12) = 30.25643716 deg
(A=B) = 36.86989765 - 30.25643716 = 6.613460488
tan (A-B) = tan 6.613460488 = 0.115942029
Conclusion: What was typed and solved at A is wrong.
What should have been typed and solved at B is right.
Step-by-step explanation:
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Step-by-step explanation:
use this formula directly
