Question

tanA = √3
tanB = 1√3
Find the value of (A+B)​

Answer 1

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$\longmapsto \sf \tan A = \sqrt{3}$

$\longmapsto \sf \tan A = \tan60 \degree$

$\longmapsto\boxed{ \sf A =60\degree}$

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$\longmapsto \sf\tan B = \dfrac{1}{\sqrt{3} }$

$\longmapsto \sf\tan B = \tan30 \degree$

$\longmapsto \boxed{\sf A =30\degree}$

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Therefore

$\longmapsto \sf A + B = 60 + 30$

$\longmapsto \boxed{\sf A + B = 90}$