Question

Tana=4/3 & cosb=-5/13 find sin(a+b)

Answer 1

Step-by-step explanation:

we know that

tana= perpendicular/ bsse

tana= 4/3

and by Pythagoras theorem,

hypotnuos square = perpendicular square +base square

hypotnuos = 4^2+3^2

= root25

=5

similarly cosb=base/hypotnuos

cosb= 5/13

so perpendicular = root13×13- 5×5

169-25

P= 144root

so p = 12

now sina= P/H= 4/5

and sinb= P/H= 12/13

sina+sinb= 4/5+12/13

= 4×13+12×5/65

= 52+60/65= 112/65 is the answer

I hope this well help you