tanA=4/3 find value sinA and cosA solve the question in detail
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Answered by
13
TanA=opp. Side/ adjacent side
TanA=4/3
While comparing we get
Opp. Side =4 and adj. Side=3
By Pythagoras theorem
4^2+3^2=hypo.^2
16+9=25
Hypo=√25=5
We know that
SinA=opp.side/hypo.
SinA=4/5
And
cosA=adj.side/hypo.
cosA=3/5
TanA=4/3
While comparing we get
Opp. Side =4 and adj. Side=3
By Pythagoras theorem
4^2+3^2=hypo.^2
16+9=25
Hypo=√25=5
We know that
SinA=opp.side/hypo.
SinA=4/5
And
cosA=adj.side/hypo.
cosA=3/5
Answered by
17
Tan A = 4/3
=> Sec² A = 1 + 4²/3²
= (3² + 4²)/3²
= 25/3²
=> Sec A = +5/3 or -5/3
=> Cos A = 3/5 or -3/5
=> Sin A = Cos A * Tan A
= 4/5 or - 4/5
=> Sec² A = 1 + 4²/3²
= (3² + 4²)/3²
= 25/3²
=> Sec A = +5/3 or -5/3
=> Cos A = 3/5 or -3/5
=> Sin A = Cos A * Tan A
= 4/5 or - 4/5
kvnmurty:
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