Question

TanA=5/6 then (8sina-4cosa)/(cosa+2sina)= ?​

Answer 1

Answer:

given 6tanA-5 = 0

so,. tanA. =5/6. = p/b

so, by Pythagoras theorem:

h² = p²+b²

h = √61

so, 3sinA -cosA/5cosA+9sinA

= 15/√61 - 6/√61\ 30/√61+ 45/√61

= 9/√61 \ 75/√61

= 9/75

= 3/25 ANS ..

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Answer 2

Step-by-step explanation:

I hope that you will understand