Question

tanA=7/24 find the value of 2sin^2 A-(1+cosA) (1-cosA)÷sinA​

Answer 1

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$\frac{2 {sin}^{2} A - (1 + cosA)(1 - cosA)}{sinA} \\ \\ \frac{2 {sin}^{2} A - (1 - {cos}^{2} A)}{sinA} \\\\ \frac{2 {sin}^{2} A - {sin}^{2} A}{sinA} \\ \\\frac { {sin}^{2} A}{sinA} = sinA$

$tanA = \frac{7}{24} \\ adjacent \: side = 7 \\ opposite \: side = 24 \\ hypotenuse = \sqrt{ {7}^{2} + {24}^{2} } = 25 \\ \\ sinA = \underline{\underline{ \frac{24}{25}}}\\\\\frac{2 {sin}^{2} A - (1 + cosA)(1 - cosA)}{sinA} =\underline{\underline{ \frac{24}{25}}}$