Question

tanA=a-b\a+b than sinA=?

Answer 1

so given height of a right angle triangle = a - b

given base of a right angle triangle = a +b


use Pythagoras theorem we get
hypotenuse = √{(a - b)² + (a + b)²}
= √{2(a² + b²)}


so sin θ=
(a - b)/√{2(a² + b²)}

Thanks, I hope it gotta help.
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