Math, asked by sweprnaep6831, 1 year ago

tanA=a/b is than bsinA-acosA/bsinA+acosA

Answers

Answered by jayanth2190

0

tanA=a/b
tanA=SinA/CosA=a/b
sinA= a. cosA=b
LHS= ba-ab/ba+ab=0

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