Question

tanA+cot A=sec A.cosecA​

Answer 1

As u know tanA=sinA/cosA(eq1)

Also cotA=cosA/sinA(eq2)

Applying eq1 & eq2 in the question,

(sinA/cos A)+(cosA/sinA)

Cross multiplying⬆️

(sin²A+cos²A)/(sinAcosA)

Since sin²A+cos²A=1

So

the question becomes

➡️1/sinAcosA

ie cosecAsecA

Hope it helped u ☺️