Question

TanA+cotA=2 then find the value of tan2A+cot2A

Answer 1

Answer:

Step-by-step explanation:

This is a bit of a trick question; the answer is 2. First, remember that cotA = 1/tanA. Then let x = tanA. The equation becomes:

x + (1/x) = 2

which rearranges to

x² - 2x + 1 = 0

(x-1)² = 0,

so x = 1. Therefore tanA = cotA = 1, and A = 45°.

Since tan45° = cot45° = 1, then tan^10(45°) = cot^10 (45°) = 1^10 = 1 as well, and hence

tan^10A + cot^10A = 2.

Answer 2

Answer:

Hi there !

Hope you understand my answer which is attached here.