Math, asked by saklecha122anugya, 1 year ago

TanA+cotA=3 find the value of tan2A+cos2A

Answers

Answered by mohit7983
1
tanA-cotA=3^1/2 , squaring both sides
tan^2A-2.tanA cotA+cot^2A=3
tan^2A-2+cot^2A=3
tan^2A+cot^2A=3+2=5
tan^2A+2+cot^2A=5+2
(tanA+cotA)^2=7
tanA+cotA=+/-(7)^1/2
tan^2A-cot^2A=(tanA+cotA)(tanA+cotA)
= +/-(7)^1/2×(3)^1/2
= +/-(21)^1/2 , Answer

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