Question

tanA/CotA=
plz answer it fast​

Answer 1

[HeY Mate]

Answer:

Solution:

$= > \frac{tanA}{cotA} \\ \\ = > \frac{ \frac{sinA}{cosA} }{ \frac{cosA}{sinA} } \\ \\ = > \frac{sinA {}^{2} }{cosA {}^{2} } \\ \\ = > tanA {}^{2}$

Hence, tanA/cotA = tan^2 A.

Using Identity:

$tanA = \frac{sinA}{cosA} \\ cotA = \frac{cosA}{sinA}$

I Hope It Helps You✌️

Answer 2

$\frac{ \tan( \alpha ) }{ \cot( \alpha ) } \\ \frac{ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } }{ \frac{ \cos( \alpha ) }{ \sin( \alpha ) } } \\ \frac{ \sin( \alpha ) \times \sin( \alpha ) }{ \ \cos( \alpha ) \times \cos( \alpha ) } \\ \frac{ { \sin( \alpha ) }^{2} }{ { \cos( \alpha ) }^{2} } \\ { \tan( \alpha ) }^{2}$