tanA+cotA= secA cosecA
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Answered by
0
Answer:
tanA+cotA= secA cosecA
Solution,
LHS
= tanA+cotA
= sinA/cosA + cosA/sinA
= sin^2A + cos^2A/cosA.sinA
= 1/cosA.sinA
= secA cosecA
hope it helps you!!!
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