Question

tanA:cotB = 2 , thus (sinA+B):(sinA-B)=?​

Answer 1

Your question will be

tanA:cotB =2, thus sin(A+B):sin(A-B) =?

Exact Interesting Answer :

Given.. tan A : cot B=2

or, (sin A/ cos A):(cos B/sin B)=2

or, sin A cos B ÷ cos A sin B =2

or, sin A cos B = 2 cos A sin B

.... (i)

using (i) :

sin A cos B - cos A sin B =cos A sinB

or, sin(A-B)= cos A sin B

using (i) :

sin A cos B + cos A sin B =3cos A sinB

or, sin(A+B)= 3 cos A sin B

NOW, (seems interesting??)

sin(A+B):sin(A-B)

= 3cos A sin B : cos A sin B

=3:1 Ans.

Hehe, patner i solved it at 2:00am...nd gona crazy.. (>ö<)✿

now send me the pg.no. from where u gve da ques