Question

TanA=root3 then,solve sinA. cosC+cosA. sinc​

Answer 1

${\huge{\bold{\underline{☯︎Answer✍︎}}}}$

give that

tan a = √3

tan a = tan 60

a = 60

we know that

sum of all sides are 180

than

∠a + ∠b + ∠c = 180

60 + 90 + ∠c = 180

∠c = 180-150

∠c = 30

in the trignometry there is one formula

that is

sin(a+c) = sin a × cos c + cos a × sin c

then

sin 60 × cos 30 + cos 60 × sin 30 = sin (60 + 30)

= sin 90

= 1.

Answer 2

$\large \tt \green {answer}$

give that

tan a = √3

tan a = tan 60

a = 60

we know that

sum of all sides are 180

than

∠a + ∠b + ∠c = 180

60 + 90 + ∠c = 180

∠c = 180-150

∠c = 30

in the trignometry there is one formula

that is

sin(a+c) = sin a × cos c + cos a × sin c

then

sin 60 × cos 30 + cos 60 × sin 30 = sin (60 + 30)

= sin 90

= 1.