tanA/secA+1+secA+1/tanA=2cosecA
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Answer:
tanA/secA+1+secA+1/tanA
=tan²A+(secA+1)²/tanA(secA+1)
=tan²A+sec²A+2secA+1/tanA(secA+1)
=2sec²A+2secA/tanA(secA+1)
=2secA(secA+1)/tanA(secA+1)
=2secA/tanA
=2cosecA
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