Math, asked by cranu8535, 7 months ago

tanA/secA+1+secA+1/tanA=2cosecA

Answers

Answered by sandy1816

4

Answer:

tanA/secA+1+secA+1/tanA

=tan²A+(secA+1)²/tanA(secA+1)

=tan²A+sec²A+2secA+1/tanA(secA+1)

=2sec²A+2secA/tanA(secA+1)

=2secA(secA+1)/tanA(secA+1)

=2secA/tanA

=2cosecA

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