Math, asked by Thaju1999, 9 months ago

(tanA+secA-1)÷(tanA-secA+1)=(1+sin)÷cosA

Answers

Answered by Anonymous

4

Answer:

Step-by-step explanation:

LHS: tanA+secA-1/tanA-secA+1

(tanA+secA)-(sec^2A-tan^2A)/tanA-secA+1

tanA+secA-[(secA+tanA)(secA-tanA)]/tanA-secA+1

(tanA+secA)[1-(secA-tanA)]/tanA-secA+1

(tanA+secA)[1-secA+tanA]/tanA-secA+1

secA+tanA

1/cosA+sinA/cosA

1+sinA/cosA:LHS

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