Question

tanA+secA-1/tanA-secA-+1=1+sinA/cos A​

Answer 1

Answer:

change tanAto SinA/CosA and secA to 1/cosA and then solve it....

U will surely get the answer ...

hope this helps u....

Answer 2

Step-by-step explanation:

multiply LHS by cosA /cosA to get

(sinA+1-cosA) / (sinA-1+cosA)

multiply again by cosA/cosA to get

(sinA.cosA+cosA-cos^2A) / cosA(sinA-1+cosA)

= ( cosA(1+sinA) - (1-sin^2A) ) / cosA(sinA-1+cosA)

= ( cosA(1+sinA) - (1+sinA)(1-sinA) ) / cosA(sinA-1+cosA)

= ( (1+sinA)(cosA-1+sinA) ) / cosA(sinA-1+cosA)

= (1+sinA)/cosA