Math, asked by kavya877, 10 months ago

tanA+secA-1/tanA-secA+1 =1+sinA/cosA

Answers

Answered by sandy1816

1

Step-by-step explanation:

(tanA+secA)-1/(tanA-secA+1)

=(tanA+secA)-(sec²A-tan²A)/(tanA-secA+1)

=(secA+tanA)(1-secA+tanA)/(tanA-secA+1)

=secA+tanA

=1+sinA/cosA

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