Math, asked by bt212005, 10 months ago

(tanA+secA-1)/(tanA-secA+1) = (1+sinA)/cosA​

Answers

Answered by ratanvoleti
0

Answer:

Step-by-step explanation:

To prove:

( tanA + secA -1)/( tanA- secA+1) = (1+sinA)/cosA

Proof:

(tanA - secA) - (sec2A - tan2A)/tanA + 1 - secA

(tanA - secA) (1 - (secA - tanA))/tanA + 1 - secA

(tanA - secA) (1 - secA + tanA)/tanA + 1 - secA

sec A + tan A

1/cosA + sinA/cosA

1 + sinA/cosA

Hence, Proved.

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