Question

tanA+secA-1/tanA-secA+1=1+sinA/cosA=cosA/1-sinA​

Answer 1

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

To prove:

( tanA + secA -1)/( tanA- secA+1) = (1+sinA)/cosA

Proof:-

(tanA - secA) - (sec2A - tan2A)/tanA + 1 - secA

(tanA - secA) (1 - (secA - tanA))/tanA + 1 - secA

(tanA - secA) (1 - secA + tanA)/tanA + 1 - secA

sec A + tan A

1/cosA + sinA/cosA

1 + sinA/cosA

Hence, Proved

ᴍʀ ꜱʜᴀʀᴇᴇꜰ(｡♥‿♥｡)

Answer 2

Answer:

To prove:

( tanA + secA -1)/( tanA- secA+1) = (1+sinA)/cosA

Proof:-

(tanA - secA) - (sec2A - tan2A)/tanA + 1 - secA

(tanA - secA) (1 - (secA - tanA))/tanA + 1 - secA

(tanA - secA) (1 - secA + tanA)/tanA + 1 - secA

sec A + tan A

1/cosA + sinA/cosA

1 + sinA/cosA

Hence, Proved

Step-by-step explanation: