tanA+secA-1/tanA-secA+1 = 1+sinA/ cosA prove that
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= tan A + sec A - (sec square - tan square A ) / tan A - sec A + 1
= tan A + sec A + ( 1 + tan A - sec A) / tan A - sec A + 1
= tan A + sec A
= sin A / Cos A + 1 / cos A
= 1 + sin A / Cos A
= Hence LHS = RHS
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= tan A + sec A + ( 1 + tan A - sec A) / tan A - sec A + 1
= tan A + sec A
= sin A / Cos A + 1 / cos A
= 1 + sin A / Cos A
= Hence LHS = RHS
please mark as brainliest if you like so
rahulkumarmandp5veal:
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