Math, asked by brainliestoop, 1 year ago

[ ( tanA ) / ( secA - 1 ) ] + [ ( tanA ) / ( secA + 1 ) ] = 2 cosecA..
Solve this question by taking LHS or RHS ... brainliest will get 95 points but any S.P.A.M. will be reported..
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Do it on a paper and attach the photo of that..

Answers

Answered by Anonymous
5

ANSWER:

Refer to the attachment for the answer...

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Attachments:
Answered by NeverMind11
1

LHS = tanA/secA - 1 + tanA/secA + 1

= sinA/cosA / 1/cosA - 1 + sinA/cosA / 1/cosA + 1 [because tan A = sin A / cos A and sec A = 1 / cos A]

= sinA/cosA / (1 - cosA) / cosA + sinA/cosA / (1 + cosA) / cos A

= sinA / 1 - cosA + sinA / 1 + cos A

= [sinA (1 + cosA) + sinA (1 - cosA)] / (1 - cosA) (1 + cosA)

= [sinA + sinAcosA + sinA - sinAcosA] / 1 - cos(sq) A

= 2sinA / sin(sq) A [From identity: sin(sq) A + cos(sq) A = 1]

= 2 / sin A

= 2 x 1 / sinA

=2 cosecA

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