Math, asked by smileoli507ozye1q, 1 year ago

(tanA-secA+1)/(tanA+secA-1)=cosA/(1+sinA)

Answers

Answered by zdm786

(tanA-secA+1)/(tanA+secA-1)
(tanA-secA+1)/tanA+secA-(sec^2A-tan^2A)
(tanA-secA+1)/tanA+secA-(secA+tanA)(secA-tanA)
(tanA-secA+1)/(secA+tanA)(1+tanA-secA)
1/secA+tanA
1/(1/cosA)+(sinA/cosA)
cosA/(1+sinA) proved

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