Question

tanA-secA+1/tanA+secA-1=cosA/1+sinA

Answer 1

It's really easy

see the attachment

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Answer 2

ANSWER=

(secA+tanA-(sec^2 A - tan ^2A)) )/tanA-secA+1) as sec^2 A= 1 + tan ^2 A so 1= sec^2 A - tan ^2 A = (sec A + tan A - (sec A + tan A) ( sec A - tan A)) / ( tanA-secA+1) = ( sec A + tan A ) ( 1- (sec A - tan A)/ ( tanA-secA+1) = (sec A + tan A)/(+ tan A - sec A)/(tan A- sec A+ 1) = (sec A + tan A) = 1/cos A + sin A/ cos A = (1+ sin A)/ cos A = (1 + sin A )(1- sin A)/(cos A (1- sin A)) = (1- sin ^2 A/(cos A (1- sin A)) = cos ^2 A / (cos A (1- sin A)) = cos A /(1- sin A) proved

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