Math, asked by sona135, 1 year ago

tanA+secA-1÷tanA-secA+1=cosA÷1-sinA

Answers

Answered by Anonymous
2
tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosA

LHS = tanA + secA -1 / tanA - secA + 1

= tanA + secA + tan2A - sec2A / tanA - secA + 1

as tan2A + 1 = sec2A

= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1

= tanA + secA( 1 + tanA - secA) / tanA - secA + 1

=tanA + secA

= sinA / cosA + 1/cosA

= sinA + 1 / cosA


sona135: thanks
sona135: alot
Anonymous: welcome
Similar questions