CBSE BOARD XII, asked by ak1843788, 5 months ago

tanA/secA-1+tanA/secA+1 = cotA

Answers

Answered by Anonymous

1

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosA

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosALHS = tanA + secA -1 / tanA - secA + 1

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosALHS = tanA + secA -1 / tanA - secA + 1= tanA + secA + tan2A - sec2A / tanA - secA + 1

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosALHS = tanA + secA -1 / tanA - secA + 1= tanA + secA + tan2A - sec2A / tanA - secA + 1as tan2A + 1 = sec2A

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosALHS = tanA + secA -1 / tanA - secA + 1= tanA + secA + tan2A - sec2A / tanA - secA + 1as tan2A + 1 = sec2A= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosALHS = tanA + secA -1 / tanA - secA + 1= tanA + secA + tan2A - sec2A / tanA - secA + 1as tan2A + 1 = sec2A= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1= tanA + secA( 1 + tanA - secA) / tanA - secA + 1

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosALHS = tanA + secA -1 / tanA - secA + 1= tanA + secA + tan2A - sec2A / tanA - secA + 1as tan2A + 1 = sec2A= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1= tanA + secA( 1 + tanA - secA) / tanA - secA + 1=tanA + secA

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosALHS = tanA + secA -1 / tanA - secA + 1= tanA + secA + tan2A - sec2A / tanA - secA + 1as tan2A + 1 = sec2A= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1= tanA + secA( 1 + tanA - secA) / tanA - secA + 1=tanA + secA= sinA / cosA + 1/cosA

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosALHS = tanA + secA -1 / tanA - secA + 1= tanA + secA + tan2A - sec2A / tanA - secA + 1as tan2A + 1 = sec2A= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1= tanA + secA( 1 + tanA - secA) / tanA - secA + 1=tanA + secA= sinA / cosA + 1/cosA= sinA + 1 / cosA

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